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Testing Identities

In this worksheet, students test the validity of the given identities.

'Testing Identities' worksheet

Key stage:  KS 3

Curriculum topic:  Algebra

Curriculum subtopic:  Understand Expressions, Equations, Inequalities, Terms and Factors

Difficulty level:  

Worksheet Overview

QUESTION 1 of 10

In this worksheet, we will test the truth of identities by substituting different values for the letters.

Letters are not just used in equations. They can be used in identities which means that the two sides of the expressions match for any values you choose for the letters, and the sides are separated by a ≡ sign.  

 

a + b ≡ b + a


p × q ≡ q × p

 

Example

 

Substitute different values for the letters and say whether or not this is true?

5 × (a + 7)5 × a + 7

 


Answer


Let's try a = 2

On the left, we get 5 x 9 = 45.

On the right, we get 5 x 2 + 7 = 10 + 7 = 17

These do not match, so the identity is false.

 

Hint

Try several values if you find the identity is true, including zero and a negative number.  

Just to be sure!

Substitute different values for the letters and say whether or not this is true:

4 × x ≡ x + x + x + x + x

Yes

No

Substitute different values for the letters and say whether or not this is true:

a + b + c ≡ c − b + a

Yes

No

Substitute different values for the letters and say whether or not this is true:

5 × (a + 7) ≡ 5 × a + 7

Yes

No

Substitute different values for the letters and say whether or not this is true:

3 × (a + b) ≡ 3 × a + 3 × b

Yes

No

Substitute different values for the letters and say whether or not this is true:

a + b + c ≡ c + b + a

Yes

No

Substitute different values for the letters and say whether or not this is true:

5(a + 7) ≡ 5a + 35

Yes

No

Substitute different values for the letters and say whether or not this is true:

4 × n ≡ n + n + n + n

Yes

No

Substitute different values for the letters and say whether or not this is true:

14 + a ≡ a + 14

Yes

No

Substitute different values for the letters and say whether or not this is true:

a - 14 ≡ 14 - a

Yes

No

  • Question 1

Substitute different values for the letters and say whether or not this is true:

4 × x ≡ x + x + x + x + x

CORRECT ANSWER
No
EDDIE SAYS
To prove an inequality is wrong, we only have to use one number. If this is incorrect, it cannot be an identity. If we use x = 2, this gives us 8 = 10 which is incorrect.
  • Question 2

Substitute different values for the letters and say whether or not this is true:

a + b + c ≡ c − b + a

CORRECT ANSWER
No
EDDIE SAYS
To prove an inequality is wrong, we only have to use one number. If this is incorrect, it cannot be an identity. If we use a = 1, b = 2 and c = 3, this gives us 6 = 4 which is incorrect.
  • Question 3

Substitute different values for the letters and say whether or not this is true:

5 × (a + 7) ≡ 5 × a + 7

CORRECT ANSWER
Yes
EDDIE SAYS
This will work for any value of a
  • Question 4

Substitute different values for the letters and say whether or not this is true:

3 × (a + b) ≡ 3 × a + 3 × b

CORRECT ANSWER
Yes
EDDIE SAYS
This will work for any value of a and b
  • Question 5

Substitute different values for the letters and say whether or not this is true:

a + b + c ≡ c + b + a

CORRECT ANSWER
Yes
EDDIE SAYS
This will work for any values of a, b and c
  • Question 6

Substitute different values for the letters and say whether or not this is true:

5(a + 7) ≡ 5a + 35

CORRECT ANSWER
Yes
EDDIE SAYS
This will work for any value of a
  • Question 7

Substitute different values for the letters and say whether or not this is true:

4 × n ≡ n + n + n + n

CORRECT ANSWER
Yes
EDDIE SAYS
This will work for any value of n
  • Question 8

Substitute different values for the letters and say whether or not this is true:

14 + a ≡ a + 14

CORRECT ANSWER
Yes
EDDIE SAYS
This will work for any value of a
  • Question 9

Substitute different values for the letters and say whether or not this is true:

a - 14 ≡ 14 - a

CORRECT ANSWER
No
EDDIE SAYS
To prove an inequality is wrong, we only have to use one number. If this is incorrect, it cannot be an identity. If we use a=2, this gives us -12 = 12 which is incorrect.
---- OR ----

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