Solving inequalities can be simple if we follow a couple of golden rules:

**1)** Treat them in the same way as an equation.

**2)** If you want to switch the **x** in a solution set from the right to the left side, you have to switch the sign (i.e.** 1 > x **is the same as **x > 1**).

A quick word on the language, when we are dealing with** inequalities**, we aren't finding a **solution** (this word applies to **equations** only), we are finding a **solution set**.

**e.g. Find the solutions for 2x + 1 < 5x + 3.**

**Step 1: **

We have a value of **x** on both sides, so we have to eliminate one of them.

Always get rid of the smaller one, as this helps to avoid negatives.

**3x + 1 < 5x + 3**

**3x + 1 - 3x < 5x + 3 - 3x**

**1 < 2x + 3**

**Step 2:**

Now let's isolate our** x**:

**1 < 2x + 3**

**1 - 3 < 2x + 3 - 3**

**-2 < 2x**

**-2 ÷ 2< 2x ÷ 2**

**-1 < x**

**Step 3: **

Switch the inequality over if necessary:

**x > -1**

Now let's look at another example where our inequality has** three **parts.

**e.g. Find the solutions for -5 ≤ 3x + 1 ≤ 7.**

The key thing to remember is that we have to do the **same to all** parts of the inequality:

**-5 ≤ 3x + 1 ≤ 7**

**-5 - 1 ≤ 3x + 1 - 1 ≤ 7 - 1**

**-6 ≤ 3x ≤ 6**

**-6 ÷ 3≤ 3x ÷ 3 ≤ 6 ÷ 3**

**-2 ≤ x ≤ 2**

In this activity, we will find solutions for complex inequalities where we may need to switch the sign at the end or may involve more than two elements.

Our working for these questions can be long and complex, so make sure you have a pen and paper handy to record yours and then compare it to what our maths teacher has written as an example solution.