In this activity, we will be looking at more complex quadratic equations, which **can** be solved by factorising.

The method of factorising a quadratic expression in the form **ax² + bx + c **into two brackets is covered in another activity.

If you haven't completed this yet or are not feeling totally confident with this skill, it would be best to review this before continuing here.

**e.g. 2x² + x - 3 = 0**

So, the equation **2x****² + x - 3 = 0** can be factorised into two brackets in the form:** (x - 1)(2x + 3)**

Now, remember that each our brackets will be multiplied together to give the answer **0**.

If I tell you that I have multiplied together two numbers and the answer is zero, can you tell me anything about my two numbers?

Well, you should be able to tell me that at least one of my numbers is zero itself.

Going back to our equation, this means that either: **(x - 1) = 0** or **(2x + 3) = 0** (They cannot both be zero.)

If **x - 1 = 0** then **x = 1 **is a solution.

Alternatively, if **2x + 3 = 0** then **x = -3/2 (-1.5)** is a solution.

So there are two possible solutions to this quadratic equation: **x = 1 **and **x = -1.5**

It is a feature of quadratic equations that they nearly always have **two solutions**.

Here's another example, this time we'll just include the lines of working you would need to show:

**6n² - 5n - 4 = 0**

**(2n + 1)(3n - 4) = 0**

Either **2n + 1 = 0 **or** 3n - 4 = 0**

So **n = -1/2 **or** n = 4/3**

Finally, we'll look at one more example:

**4z(z - 1) = 3**

Now, this equation looks like it has already been factorised.

However, you will notice the right-hand side is **3**, not **0**.

**Quadratic equations can only be solved if the right-hand side is zero.**

So we need to **rearrange** the equation first and this means we must expand the brackets as our starting point:

**4z² - 4z = 3**

Now subtract 3 from both sides:

**4z² - 4z - 3 = 0**

Now our equation is in the correct form for us to factorise into two brackets and then solve:

** 4z² - 4z - 3 = 0**

**(2z - 3)(2z + 1) = 0**

Either **2z - 3 = 0** or** 2z + 1 = 0**

So** z = 3/2 **or **z = -1/2**

Ready to try some for yourself now?

In this activity, we will solve quadratic equations by ensuring that they conform to the style of **ax² + bx + c = 0** first, then factorising them to find possible values for our variables.