The nth term of a quadratic sequence is expressed in the form **an ^{2} + bn + c**.

To find the correct expression, we need to find the values for **a**, **b** and **c**.

It is quite useful to notice that an nth term is made up of two distinct parts:

Quadratic Nth term = Quadratic Element + Linear Element

an^{2} + bn + c

Although this may look daunting, finding the nth term of a quadratic sequence can be quite straightforward.

Just follow the steps laid about below and you won't go astray.

**e.g. Find the nth term for this sequence: 5, 15, 29, 47, ...**

**Step 1: **Find a

There is a golden rule we **must **apply here: *The value of a will always be half the second difference.*

The difference between the first and second terms is 10.

The difference between the second and third terms is 14.

The difference between the third and fourth terms is 18.

We can see that the second difference is 4, so the value of **a **is **2** (4 × 0.5).

**Step 2:** Set up a table to support you

Position | 1 | 2 | 3 | 4 |

an^{2} = 2n^{2} |
||||

bn + c | ||||

Target | 5 | 15 | 29 | 47 |

In this table, the 'Position' is just the value of **n** (i.e. where it is in the sequence).

We have just found the value of **a **so we can fill in the second line by substituting values of **n** into **2n**^{2}:

Position | 1 | 2 | 3 | 4 |

an^{2} = 2n^{2} |
2 | 8 | 18 | 32 |

bn + c | ||||

Target | 5 | 15 | 29 | 47 |

**Step 3: **Find the value of **bn + c**

In our table, we now know the value of the **quadratic element**, so we can now us this to find the** linear element**.

These are just the differences between **an ^{2}** and the target:

Position | 1 | 2 | 3 | 4 |

an^{2} = 2n^{2} |
2 | 8 | 18 | 32 |

bn + c | 3 | 7 | 11 | 15 |

Target | 5 | 15 | 29 | 47 |

We can now see that these numbers in blue (3, 7, 11, 15) form a linear sequence with an nth term of **4n - 1**.

**Step 4: **Put it all together

Earlier, we said that...

Quadratic Nth term = Quadratic Element + Linear Element

an^{2} + bn + c

** 2n ^{2} + 4n - 1 **

There are many steps here but, if we follow them systematically, we will reach an accurate quadratic expression each time.

In this activity, we will find quadratic expressions which represent sequences and apply these to find unknown terms.

As these methods can be long and complex, it is a good idea to have a pen and paper handy so you can compare your working to what our maths teacher has written as an example.