Two lines of gradient m1 and m2 are perpendicular if m1m2 = -1
Find the gradient of a line perpendicular to the line with equation 4y - 3x = - 2
We must first rearrange this equation to make y the subject.
4y - 3x = -2
4y = 3x - 2
y = ¾x - ½
The gradient, m1, of y = ¾x - ½ is the coefficient of x, so
m1 = ¾
m1m2 = -1, where m2 is the gradient of a line perpendicular to the given line.
¾m2 = -1
m2 = -4/3