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Histograms

In this worksheet, students understand frequency densities and how to read information from a histogram and its associated table of data.

'Histograms' worksheet

Key stage:  KS 4

Curriculum topic:  Statistics

Curriculum subtopic:  Interpret and Construct Tables and Line Graphs for Time Series Data

Difficulty level:  

down

Worksheet Overview

QUESTION 1 of 10

A histogram is a chart consisting of bars to represent continuous grouped data.

The class intervals may be unequal and there are no gaps between the bars.

Frequency is proportional to the areas of the bars.

 

Frequency density  = frequency
width of class interval

 

Example

A company has 725 workers

The following table shows the distribution of weekly wages.

 

Weekly Wages (£) frequency (f)
0 ≤ w < 200 200
200 ≤ w < 300 200
300 ≤ w < 350 125
350 ≤ w < 500 150
500 ≤ w < 600 50
Total 725

 

Work out the Frequency Densities for this distribution and draw a histogram to display this information.

 

Answer

We extend the table with two new columns to show class width and Frequency density.

Using the formula below, we work out the Frequency density for each class width.

 

Frequency density  = frequency
width of class interval

  

 

 

Weekly Wages (£) frequency (f) Class width Frequency density
0 ≤ w < 200 200 200   200 ÷ 200 = 1
200 ≤ w < 300 200 100   200 ÷ 100 = 2
300 ≤ w < 350 125 50   125 ÷ 50 = 2.5
350 ≤ w < 500 150 150   150 ÷ 150 = 1
500 ≤ w < 600 50 100   50 ÷ 100 = 0.5
Total  725    

 

 

 

 

 

 

 

 

 

 

Weekly wages are then plotted against Frequency density to produce the following histogram.

 

 

For this worksheet, you will need the formula:

Frequency = Frequency Density × Class Width

A company has 725 workers.

The following histogram shows the distribution of weekly wages.

Work out the frequency for the 0 ≤ w < 200 class interval.

A company has 725 workers.

The following histogram shows the distribution of weekly wages.

Work out the frequency for the 300 ≤ w < 350 class interval.

A company has 725 workers.

The following histogram shows the distribution of weekly wages.

Work out the frequency for the 350 ≤ w < 500 class interval.

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 10 ≤ a < 25 class interval.

 

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 30 ≤ a < 40 class interval.

 

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 25 ≤ a < 30 class interval.

 

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 40 ≤ a < 55 class interval.

 

The following histogram shows the distribution of the lengths of adverts on one television channel during a particular day.

Work out the frequency for the 0 ≤ t < 10 class interval.

 

The following histogram shows the distribution of the lengths of adverts on one television channel during a particular day.

Work out the frequency for the 10 ≤ t < 15 class interval.

 

The following histogram shows the distribution of the lengths of adverts on one television channel during a particular day.

Work out how many TV adverts have been surveyed in total.

 

  • Question 1

A company has 725 workers.

The following histogram shows the distribution of weekly wages.

Work out the frequency for the 0 ≤ w < 200 class interval.

CORRECT ANSWER
200
EDDIE SAYS
Class width = 200 - 0 = 200
Frequency = Frequency Density × Class Width = 1 × 200 = 200
  • Question 2

A company has 725 workers.

The following histogram shows the distribution of weekly wages.

Work out the frequency for the 300 ≤ w < 350 class interval.

CORRECT ANSWER
125
EDDIE SAYS
Class width = 350 - 300 = 50
Frequency = Frequency Density × Class Width = 2.5 × 50 = 125
  • Question 3

A company has 725 workers.

The following histogram shows the distribution of weekly wages.

Work out the frequency for the 350 ≤ w < 500 class interval.

CORRECT ANSWER
150
EDDIE SAYS
Class width = 500 - 350 = 150
Frequency = Frequency Density × Class Width = 1 × 150 = 150
  • Question 4

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 10 ≤ a < 25 class interval.

 

CORRECT ANSWER
30
EDDIE SAYS
Class width = 25 - 10 = 15
Frequency = Frequency Density × Class Width = 2 × 15 = 30
  • Question 5

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 30 ≤ a < 40 class interval.

 

CORRECT ANSWER
35
EDDIE SAYS
Class width = 40 - 30 = 10
Frequency = Frequency Density × Class Width = 3.5 × 10 = 35
  • Question 6

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 25 ≤ a < 30 class interval.

 

CORRECT ANSWER
13
EDDIE SAYS
Class width = 30 - 25 = 5
Frequency = Frequency Density × Class Width = 2.6 × 5 = 13
  • Question 7

The following histogram shows the distribution of ages of people staying at a hotel.

Work out the frequency for the 40 ≤ a < 55 class interval.

 

CORRECT ANSWER
18
EDDIE SAYS
Class width = 55 - 40 = 15
Frequency = Frequency Density × Class Width = 1.2 × 15 = 18
  • Question 8

The following histogram shows the distribution of the lengths of adverts on one television channel during a particular day.

Work out the frequency for the 0 ≤ t < 10 class interval.

 

CORRECT ANSWER
8
EDDIE SAYS
Class width = 10 - 0 = 10
Frequency = Frequency Density × Class Width = 0.8 × 10 = 8
  • Question 9

The following histogram shows the distribution of the lengths of adverts on one television channel during a particular day.

Work out the frequency for the 10 ≤ t < 15 class interval.

 

CORRECT ANSWER
12
EDDIE SAYS
Class width = 15 - 10 = 5
Frequency = Frequency Density × Class Width = 2.4 × 5 = 12
  • Question 10

The following histogram shows the distribution of the lengths of adverts on one television channel during a particular day.

Work out how many TV adverts have been surveyed in total.

 

CORRECT ANSWER
113
EDDIE SAYS
We add up all the frequencies to get:
(0.8 × 10) + (2.4 × 5) + (2.8 × 15) + (3.3 × 10) + (1.2 × 15)
= 8 + 12 + 42 + 33 + 18 = 113
---- OR ----

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