Look at the statement below.
3 | + | 4 | = | 7 | = | 1 | 2 |
5 | 5 | 5 | 5 |
3 fifths + to 4 fifths = 7 fifths.
7 fifths is a top-heavy improper fraction.
7 ÷ 5 = 1 remainder 2.
7 fifths can be changed to the mixed number "one and 2 fifths".
For example: what are the values of A, B and C in this statement?
5 | + | 6 | = | A | = | B | 4 |
7 | 7 | 7 | C |
Answer:
5 sevenths added to 6 sevenths = 11 sevenths.
11 sevenths is a top-heavy improper fraction.
11 ÷ 7 = 1 remainder 4.
11 sevenths can be changed to the mixed number "one and 4 sevenths".
This gives us:
5 | + | 6 | = | 11 | = | 1 | 4 |
7 | 7 | 7 | 7 |
Therefore,
A = 11
B = 1
C = 7