When two events occur, there are several possible outcomes.
For example, when a coin is thrown, it can land heads up (H) or tails up (T), and when a die is thrown it can land showing a 1, 2, 3, 4, 5 or 6.
So when they are both thrown, the possible outcomes are:
There are 12 possible outcomes.
So the probability of getting a head and a 6, P(H6) = 1/12
Let's have a go at some questions, making sure that we write carefully organised, systematic lists when determining all the outcomes and don't just write out the outcomes randomly.