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Use Data Relating to Osmosis

In this worksheet, students will interpret data relating to osmosis.

Worksheet Overview


Image of particles moving via osmosis



Osmosis is the diffusion of water molecules from a high concentration to a low concentration, across a partially permeable membrane.  A partially permeable membrane has holes or pores in it that allow water molecules through, but are too small to allow larger molecules through. 

During osmosis, water molecules diffuse from pure water or dilute solution to more concentrated solutions.

Dilute solutions have a high concentration of water molecules, so have a high water potential. 

Concentrated solutions have a low concentration of water molecules, so have a  low water potential.



Osmosis in Plants


Plant and animal cells are surrounded by a partially permeable cell membrane. This allows water and other small molecules to diffuse across. Plant cells additionally have a strong cell wall surrounding the membrane, which offers support and protection.


Image of plant cells in different concentrations of water



Plants require water in order to photosynthesise. The roots of a plant contain root hair cells, which are specialised cells that increase the surface area of the cells for maximum absorption of water by osmosis. In pure water, plant cells will take in water via osmosis and become firm or turgid. In a concentrated solution (not much water present), the cell loses water and starts to shrink and becomes flaccid.  


In humans, the concentration of water and salt in the blood is controlled by the kidneys. The kidneys ensure our bodies have the right concentration of water by getting rid of the excess water as urine.



Calculations Involving Osmosis


Image of weighing scales


Osmosis can be demonstrated using cubes of potatoes of roughly the same mass. By placing the cubes in different concentrations of sugar solutions, the cubes might gain or lose mass, or might even stay the same mass.

Scientists will be able to calculate the percentage change in mass to see how much mass was gained or lost - and converting to percentages often makes for easier comparison. Percentage change in mass is calculated by using the following equation:


(Final mass (g) – initial mass (g)) ÷ initial mass (g) x 100


For example, a potato cube has an initial mass of 1 g. After placing it in a sugar solution for 30 minutes, its mass was 1.1 g. Its percentage change in mass is 10%. 

(1.1 g - 1 g) ÷ 1 g x 100 = +10%

The plus sign shows there was an increase in mass. A minus sign shows a loss in mass.


The rate of water uptake can also be calculated. This gives an indication of how much water is absorbed in an hour. The rate of uptake is calculated using the following equation:


Change in mass (g) x (60 minutes ÷ duration of time in minutes)


Using the above example of the potato cube:

0.1 g x (60 mins ÷ 30 mins) = 0.2 g/hour


In the following activity, you will interpret data relating to osmosis.  

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