If you want to define a circle, there are two pieces of information that you need - the centre and the radius.

At GCSE level, you only have to deal with circles that have a centre of (0,0), so the only thing you really need to deal with is the **radius**.

**Is there a formula?**

Luckily yes, the equation of a circle with a centre of (0,0) is given by** x ^{2} + y^{2} = r^{2}**, where r is the radius of the circle.

**What do I have to be able to do?**

There are three things you have to be able to do when dealing with a circle. Let’s deal with them one by one.

**Example 1:**

**Find the radius of the circle**** with the equation x ^{2} + y^{2} = 64**

This is a nice, easy one, you can just match this with the general equation and you should see that r^{2} = 64.

This means that the **radius of this circle is 8**.

**Find the radius of the circle with the equation x ^{2} + y^{2} = 72**

When you have ones such as this, where r^{2} is not a square number, we have to start dealing with **surds.**

We can see that r^{2} = 72 so r = √72.

We can’t leave it like this (mathematicians always cancel, we’re a bit obsessive about it).

√72 = √36 x √2 = 6√2

So our radius, in its simplest form is **r = 6√2**

**Example 2:**

**Is the point (3,2) inside, outside or on the circle with equation x ^{2} + y^{2} = 12?**

With this, we need to think about the distance between the centre of the circle (0,0) and the point (3,2).

The only way we can do this is by using Pythagoras' Theorem:

**x ^{2} = 3^{2} + 2^{2} → x = √13**

We can now look at the radius of the circle:

**r ^{2} = 12 → r = √12**

We can now see that the distance between the point and the centre of the circle (√13) is larger than the radius of the circle (√12) so the point (3,2) must be **outside **the circle.

**Example 3:**

**Give a point (A) with integer coordinates that sits on the circle x ^{2} + y^{2} = 20**

While we’re only asked for one, there are actually eight that you could give as an answer.

The trick here is to look at the **square numbers **and find two that add to 20.

In this case, the numbers are** 4 and 16.**

We can therefore say that** if x = 2 and y = 4 then x ^{2} + y^{2} = 20**

So point A is **(2,4)**

To find the other seven we need to look into a few facts:

It doesn’t matter which way round you add things, which means that x and y can just be the other way round. Point B is **(4,2)**

**Squaring a negative number gives a positive.**

This will mean that the coordinates could just be reversed:

Point C is **(-2,-4) **and point D is **(-4,-2)**

You could also have a combination of positives and negatives:

** (-2,4) (2,-4) (-4,2) (4,-2)**

For this question any of the ones above would be sufficient to get the mark.

Let's have a go at some questions now.